Termination w.r.t. Q of the given QTRS could be disproven:

(0) Obligation:

Q restricted rewrite system:
The TRS R consists of the following rules:

a(x1) → x1
a(a(a(x1))) → b(x1)
b(c(x1)) → c(c(a(b(x1))))
c(x1) → x1

Q is empty.

(1) NonTerminationProof (EQUIVALENT transformation)

We used the non-termination processor [OPPELT08] to show that the SRS problem is infinite.

Found the self-embedding DerivationStructure:

b c c c c c c → b c c c c c c a b

b c c c c c c → b c c c c c c a b
by OverlapClosure OC 2

b c c c c c → b c c c c b
by OverlapClosure OC 2

b c c c → b b
by OverlapClosure OC 3

b c c c → a a a b
by OverlapClosure OC 2

b c → a b
by OverlapClosure OC 3

b c → c a b
by OverlapClosure OC 3

b c → c c a b
by original rule (OC 1)

c →
by original rule (OC 1)

c →
by original rule (OC 1)

b c c → a a b
by OverlapClosure OC 2

b c → a b
by OverlapClosure OC 3

b c → c a b
by OverlapClosure OC 3

b c → c c a b
by original rule (OC 1)

c →
by original rule (OC 1)

c →
by original rule (OC 1)

b c → a b
by OverlapClosure OC 3

b c → c a b
by OverlapClosure OC 3

b c → c c a b
by original rule (OC 1)

c →
by original rule (OC 1)

c →
by original rule (OC 1)

a a a → b
by original rule (OC 1)

b c c → c c c c b
by OverlapClosure OC 2

b c → c c b
by OverlapClosure OC 3

b c → c c a b
by original rule (OC 1)

a →
by original rule (OC 1)

b c → c c b
by OverlapClosure OC 3

b c → c c a b
by original rule (OC 1)

a →
by original rule (OC 1)

b c → c c a b
by original rule (OC 1)

(2) NO